One idea is that, due to the proximity factor, #8 will often knock off #6 and #7 (or #1 and #2, for that matter). See the following table:
1st point 2nd point played by #8 played by #8 Total ------------------------------------------ Opp# Prob% Opp# Prob% Opp# Tot% 1 1.5625 1 50 1 51.5625 2 1.5625 2 50 2 51.5625 3 3.125 3 0 3 3.125 4 6.25 4 0 4 6.25 5 12.5 5 0 5 12.5 6 25 6 0 6 25 7 50 7 0 7 50
So, there's a strong liklihood that #8 will face 7, 1 or 2
in their first tour, then 6, 5, 4, 3 in that order. That means
there should be more 8-3's than 8-4's, etc.
Comments?
